Dear friends, lets explore some c program examples
C Program Examples 1 : Input day number of week and print name of the day using switch( )
#include <stdio.h>
int main() {
int dayNumber;
// Prompt the user to enter the day number
printf("Enter the day number (1-7): ");
scanf("%d", &dayNumber);
// Use a switch statement to determine the day name
switch (dayNumber) {
case 1:
printf("Sunday\n");
break;
case 2:
printf("Monday\n");
break;
case 3:
printf("Tuesday\n");
break;
case 4:
printf("Wednesday\n");
break;
case 5:
printf("Thursday\n");
break;
case 6:
printf("Friday\n");
break;
case 7:
printf("Saturday\n");
break;
default:
printf("Invalid day number. Please enter a number between 1 and 7.\n");
break;
}
return 0;
}
Output:
Enter the day number (1-7): 6
Friday
Enter the day number (1-7): 8
Invalid day number. Please enter a number between 1 and 7.C Program Examples 2 : Input day number of week and decide whether working day or week end, using switch( )
#include <stdio.h>
int main() {
int dayNumber;
// Prompt the user to enter the day number
printf("Enter the day number (1-7): ");
scanf("%d", &dayNumber);
// Use a switch statement to determine whether it's a working day or weekend
switch (dayNumber) {
case 1:
case 2:
case 3:
case 4:
case 5:
printf("It's a working day.\n");
break;
case 6:
case 7:
printf("It's the weekend!\n");
break;
default:
printf("Invalid day number. Please enter a number between 1 and 7.\n");
break;
}
return 0;
}
Output:
Enter the day number (1-7): 5
It's a working day.C Program Examples 3 : Input marks and assign grade to a student using switch( )
#include <stdio.h>
int main() {
int marks;
// Prompt the user to enter the marks
printf("Enter the marks (0-100): ");
scanf("%d", &marks);
// Use a switch statement to assign a grade
switch (marks / 10) {
case 10:
case 9:
printf("Grade: A\n");
break;
case 8:
printf("Grade: B\n");
break;
case 7:
printf("Grade: C\n");
break;
case 6:
printf("Grade: D\n");
break;
case 5:
case 4:
printf("Grade: E\n");
break;
default:
printf("Grade: F (Fail)\n");
break;
}
return 0;
}
Output:
Enter the marks (0-100): 95
Grade: AC Program Examples 4 : Calculate Sum of 1/2 + 2/3 + 3/4 … + n terms
#include <stdio.h>
int main() {
int n;
float sum = 0.0;
// Prompt the user to enter the number of terms (n)
printf("Enter the number of terms (n): ");
scanf("%d", &n);
if (n < 1) {
printf("Invalid input. Please enter a positive integer for n.\n");
} else {
for (int i = 1; i <= n; i++) {
sum += (float)i / (i + 1);
}
// Display the sum of the series
printf("Sum of the series: %.2f\n", sum);
}
return 0;
}
Output:
Enter the number of terms (n): 5
Sum of the series: 3.55C Program Examples 5 : Calculate Sum of S = x/1 + x/2 + x/3 … + x/n
#include <stdio.h>
int main() {
int a, n, x;
float s;
printf("\nEnter value for x and n: ");
scanf("%d%d", &x, &n);
s = 0.0;
a = 1;
while (a <= n) {
s = s + x / (float)(a);
a = a + 1;
}
printf("\nSum of the series is %.2f", s);
return 0;
}
Output:
Enter value for x and n: 3 5
Sum of the series is 6.85
Note that, if input is x=3 and n=5
s = 3/1 + 3/2 + 3/3 + 3/4 + 3/5
= 3 + 1.5 + 1 + 0.75 + 0.6
= 6.85C Program Examples 6 : Generate Fibonacci series up to n terms
#include <stdio.h>
int main() {
int n, first = 0, second = 1, next, i;
// Prompt the user to enter the number of terms (n)
printf("Enter the number of terms in the Fibonacci series: ");
scanf("%d", &n);
printf("Fibonacci Series up to %d terms: ", n);
// Special case for the first two terms
if (n >= 1) {
printf("%d", first);
}
if (n >= 2) {
printf(", %d", second);
}
for (i = 3; i <= n; i++) {
// Calculate the next term by adding the previous two terms
next = first + second;
// Print the next term
printf(", %d", next);
// Update the values of first and second for the next iteration
first = second;
second = next;
}
printf("\n");
return 0;
}
Output:
Enter the number of terms in the Fibonacci series: 10
Fibonacci Series up to 10 terms: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34C Program Examples 7 : To find Pythagorean triplets in the range 1 to 25
Note:
Pythagorean triplet is a set of three numbers that satisfy the Pythagorean theorem.
For Example:
3 4 5 = 9 + 16 = 25
5 12 13 = 25 +144 = 169
#include <stdio.h>
int main() {
printf("Pythagorean Triplets in the range 1 to 25:\n");
for (int a = 1; a <= 25; a++) {
for (int b = a; b <= 25; b++) {
for (int c = b; c <= 25; c++) {
if (a * a + b * b == c * c) {
printf("%d, %d, %d\n", a, b, c);
}
}
}
}
return 0;
}
Output:
Pythagorean Triplets in the range 1 to 25:
3, 4, 5
5, 12, 13
6, 8, 10
7, 24, 25
8, 15, 17
9, 12, 15
12, 16, 20
15, 20, 25C Program Examples 8 : Sine Series
#include <stdio.h>
#include <math.h>
int factorial(int n) {
if (n == 0) return 1;
return n * factorial(n - 1);
}
double power(double base, int exponent) {
if (exponent == 0) return 1.0;
return base * power(base, exponent - 1);
}
int main() {
double x, sum = 0.0;
int n;
// Prompt the user to enter the angle in radians
printf("Enter the angle (in radians): ");
scanf("%lf", &x);
// Prompt the user to enter the number of terms
printf("Enter the number of terms: ");
scanf("%d", &n);
for (int i = 0; i < n; i++) {
int sign = (i % 2 == 0) ? 1 : -1; // Alternate signs
double term = (sign * power(x, 2 * i + 1)) / factorial(2 * i + 1);
sum += term;
}
// Display the result
printf("Sine of %.2lf radians (approximated with %d terms) is: %.6lf\n", x, n, sum);
return 0;
}
Output:
Enter the angle (in radians): 1.047
Enter the number of terms: 10
Sine of 1.05 radians (approximated with 10 terms) is: 0.865927C Program Examples 9 : Print ***** (5 Stars)
#include <stdio.h>
int main() {
// Use a loop to print five asterisks
for (int i = 0; i < 5; i++) {
printf("*");
}
// Print a newline to end the line
printf("\n");
return 0;
}
Output:
*****C Program Examples 10 : Print ***** in 5 lines
#include <stdio.h>
int main() {
// Use two nested loops to print five lines of five asterisks
for (int i = 0; i < 5; i++) { // This outer loop controls the lines
for (int j = 0; j < 5; j++) { // This inner loop controls the stars in each line
printf("*");
}
// Print a newline to move to the next line
printf("\n");
}
return 0;
}
Output:
*****
*****
*****
*****
*****C Program Examples 11 : Print left aligned triangle of stars in increasing order
#include <stdio.h>
int main() {
int rows;
// Prompt the user to enter the number of rows for the triangle
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = 1; i <= rows; i++) { // Loop through each row
for (int j = 1; j <= i; j++) { // Loop to print stars in each row
printf("*");
}
// Move to the next line for the next row
printf("\n");
}
return 0;
}
Output:
Enter the number of rows: 5
*
**
***
****
*****C Program Examples 12 : Print left aligned triangle of stars , in decreasing order
#include <stdio.h>
int main() {
int rows;
// Prompt the user to enter the number of rows for the triangle
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (int i = rows; i >= 1; i--) { // Loop through each row in decreasing order
for (int j = 1; j <= i; j++) { // Loop to print stars in each row
printf("*");
}
// Move to the next line for the next row
printf("\n");
}
return 0;
}
Output:
Enter the number of rows: 5
*****
****
***
**
*C Program Examples 13 : To Print left aligned triangle of stars, in decreasing order for n rows
#include <stdio.h>
int main() {
int n;
// Prompt the user to enter the number of rows for the triangle
printf("Enter the number of rows: ");
scanf("%d", &n);
for (int i = n; i >= 1; i--) { // Loop through each row in decreasing order
for (int j = 1; j <= i; j++) { // Loop to print stars in each row
printf("*");
}
// Move to the next line for the next row
printf("\n");
}
return 0;
}
Output:
Enter the number of rows: 7
*******
******
*****
****
***
**
*C Program Examples 14 : Print center aligned triangle of stars, in increasing order
#include <stdio.h>
int main() {
int n;
// Prompt the user to enter the number of rows for the triangle
printf("Enter the number of rows: ");
scanf("%d", &n);
for (int i = 1; i <= n; i++) { // Loop through each row
// Print spaces to center-align the stars
for (int space = 1; space <= n - i; space++) {
printf(" ");
}
// Print stars in increasing order
for (int j = 1; j <= 2 * i - 1; j++) {
printf("*");
}
// Move to the next line for the next row
printf("\n");
}
return 0;
}
Output:
Enter the number of rows: 5
*
***
*****
*******
*********
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